MySQL SUBDATE() Function

Subtract 10 days from a date and return the date:

SELECT SUBDATE("2017-06-15", INTERVAL 10 DAY);

Definition and Usage

The SUBDATE() function subtracts a time/date interval from a date and then returns the date.

SUBDATE(date, INTERVAL value unit)

OR:

SUBDATE(date, days)

Parameter	Description
date	Required. The original date
days	Required. The number of days to subtract from date
value	Required. The value of the time/date interval to subtract. Both positive and negative values are allowed
unit	Required. The type of interval. Can be one of the following values: MICROSECOND SECOND MINUTE HOUR DAY WEEK MONTH QUARTER YEAR SECOND_MICROSECOND MINUTE_MICROSECOND MINUTE_SECOND HOUR_MICROSECOND HOUR_SECOND HOUR_MINUTE DAY_MICROSECOND DAY_SECOND DAY_MINUTE DAY_HOUR YEAR_MONTH

Works in:	From MySQL 4.0

Subtract 15 minutes from a date and return the date:

SELECT SUBDATE("2017-06-15 09:34:21", INTERVAL 15 MINUTE);

Subtract 3 hours from a date and return the date:

SELECT SUBDATE("2017-06-15 09:34:21", INTERVAL 3 HOUR);

Add 2 months to a date and return the date:

SELECT SUBDATE("2017-06-15", INTERVAL -2 MONTH);